N=No2^t/d

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Solution for N=No2^t/d equation: 


(1/5-(1/5)^2-2)*x-(((1/5)^2-(6/5)-(1/5)^3+2)*y)+1/5;(2/3-(2/3)^2-2)*x-(((2/3)^2-(2/3)^3-4+2)*y)+2/3

x-(7/5) = 10

(2/3)/6 = 0

3*(16/7) = 0

-3*(16/7) = 0

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